sigh

异常处理的写法

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begin
	可能会发生异常的处理
rescue => ex
	print ex.message, "\n"	发生异常的处理
ensure
	不管是否发生异常都希望执行的处理
end

Ruby基础教程第九章

开发环境

好吧，逛了一天回来坐在电脑前，打开心爱的Atom，记录下这在成长路上迈出得一小步。

Use SimpleDateFormat#parse() to parse a String in a certain pattern into a Date.

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String oldstring = "2011-01-18 00:00:00.0";
Date date = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss.S").parse(oldstring);

Use SimpleDateFormat#format() to format a Date into a String in a certain pattern.

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String newstring = new SimpleDateFormat("yyyy-MM-dd").format(date);
System.out.Jprintln(newstring); // 2011-01-18

Update: as per your failed attempt: the patterns are case sensitive. Read the SimpleDateFormatjavadoc what the individual parts stands for. So stands for example M for months and m for minutes. Also, years exist of four digits, not five. Look closer at the code snippets I posted here above.